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Water is flowing through a capillary tub...

Water is flowing through a capillary tube at the rate of `20xx10^(-6)m^(3)//s`. Another tube of same radius and double the length is connected in series to the first tube. Now the rate of flow of water in `m^(3)s^(-1)` is

A

`10xx10^(-6)`

B

`3.33xx10^(-6)`

C

`6.67xx10^(-6)`

D

`20xx10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Q=(piPr^(4))/(8etal), Q alpha(1)/(l)`
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