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The acceleration of an object moving wit...

The acceleration of an object moving with speed v in a circle of radius r is

A

`(u^(2))/(r )` towards the centre

B

`(u)/(r )` way from the centre

C

`(u)/(r^(2))` way from the centre

D

`(r )/(u^(2))` towards the centre

Text Solution

Verified by Experts

The correct Answer is:
A
Cendripetal offorce acting on an object in unifomcircuaar motion is,
`f=(mv^(2))/(r)`
or accekeration is `(f)/(m)=(v^(2))/(r)` towards the centre.
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Knowledge Check

  • The acceleration of an object moving in a circle of radius R with uniform speed v is

    A
    `(v^(2))/( R)`
    B
    `( v^(2))/( 2R)`
    C
    `( 2v^(2))/( R ) `
    D
    `( 3v^(2))/( 2R)`

  • Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

    A
    4 m/r
    B
    `4 m// sqrt(r)`
    C
    `2 m sqrt(r)`
    D
    2 m/r

  • Centripetal force (F) on a body of mass (m) moving with uniform speed (v) in a circle of radius (r ) depends upon m, v and r. The formula for the centripetal force using theory of dimensons.

    A
    `kmv^(2)`
    B
    `(kmv^(2))/(r )`
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    `(km^(2)v^(2))/(r )`
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