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Ultraviolet light of wavelength 300nn an...

Ultraviolet light of wavelength 300nn and intensity `1.0Wm^-2` falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 `cm^2` of the surface is nearly

A

`9.61 xx 10^(14)`

B

`4.12 xx 10^(13)`

C

`1.51 xx 10^(12)`

D

`2.13 xx 10^(11)`

Text Solution

Verified by Experts

The correct Answer is:
3
`p = ((n)/(t))((hc)/(lambda))`
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Knowledge Check

  • Light of wavelength 5000 Å and intensity of 3.96 xx 10^(-3) watt//cm^(2) is incident on the surface of photo metal . If 1% of the incident photons only emit photo electrons , then the number of electrons emitted per unit area per second from the surface will be

    A
    `9.82 xx 10^(17) m^(-2)//2`
    B
    `9.82 xx 10^(13) m^(-2) // s`
    C
    `9.82 m^(-2)//s`
    D
    `none of these

  • Ultraviolet light of wavelength 66.26 nm and intensity 2 W//m^(2) falls on potassium surface by which photoelectrons are ejected out. If only 0.1% of the incident photons produce photoelectrons, and surface area of metal surface is 4 m^(2) , how many electrons are emitted per second?

    A
    `2.67 xx 10^(15)`
    B
    `3 xx 10^(15)`
    C
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  • Radiation of frequency 1.5 times the threshold frequency is incident on a photosensitive material. If the frequency of incident radiation is halved and the intensity is doubled, the number of photoelectron ejected per second becomes:

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    B
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    C
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    D
    three fourth the initial value

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