If the dimension of a physical quantity ...

If the dimension of a physical quantity are given by `M^a L^b T^c,` then the physical quantity will be

Force if a = 0, b = -1, c =-2

Pressure if a = 1, b =-1, c = -2

Velocity if a =1, b =0, c=-1

Acceleration if a = 1, b=1, c=-2

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The correct Answer is:

[Force ] = `[MLT^(-2)]`
[Pressure] = `[ML^(-1)^(-2)]`
[Velocity] = `[LT^(-1)]`
[Acceleration] = `[LT^(-2)]`

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If the dimensions of a physical quantity are given by M^(a)L^(b) T^(c) , then the physical quantity will be

velocity if a 1, b = 0, c =-1

acceleration if a = 1, b= 1, c = -2

force if a = 0, b = - 1, c = - 2

pressure if a = 1, b =-1, c = -2

Force if `a = 0, b = –1, c = – 2 `

Pressure if `a = 1, b = – 1, c = – 2 `

Velocity if `a = 1, b = 0, c = – 1`

Acceleration if `a = 1, b = 1, c = – 2`

force ,if a = -1 , b=0,c=- 2

pressure, if a=-1,b=1,c=-2

velocity , if a =1, b=0,c=1

acceleration , if a=1,b=1,c=2