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With increasing atomic number of a singl...

With increasing atomic number of a single electron species, the energy difference between two orbits

A

Increases

B

Decreases

C

Remains constant

D

First increases followed by a decrease

Text Solution

Verified by Experts

The correct Answer is:
A

`Delta E =RhC [ (1)/(n_(1)^(2)) - (1)/(n_(2)^(2)) ] xx Z^(2) " "Delta E prop Z^2`
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Whith increasing principal quantum number, the energy difference between adjacent energy levels in H-atom:

What is the difference in energy between 1s and 2p -orbitals in the hydorgen atom ? In the X-ray spectrum of Cu , radiation of 1.54 Å wavelength is emitted when an electron charges form 2p to 1s-orbital . What is the energy difference between these orbitals in copper ?

Knowledge Check

  • With increasing quantum numbers, the energy difference between adjacent energy level atoms

    A
    increases
    B
    decreases
    C
    will be same
    D
    either 'a' or 'b'
  • With increasing principal quantum number , the energy difference between adjacent energy levels in atoms

    A
    Decreases
    B
    Increases
    C
    Remains constant
    D
    Decreases for low Z and increases for high Z
  • With increasing member, the energy difference between adjacent levels in atoms.

    A
    decreases
    B
    increases
    C
    remains constant
    D
    decreases for low `Z` and increases for high `Z`
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