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With increasing atomic number of a singl...

With increasing atomic number of a single electron species, the energy difference between two orbits

A

Increases

B

Decreases

C

Remains constant

D

First increases followed by a decrease

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta E =RhC [ (1)/(n_(1)^(2)) - (1)/(n_(2)^(2)) ] xx Z^(2) " "Delta E prop Z^2`
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