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The ratio of highest possile wavelength ...

The ratio of highest possile wavelength to lowest possible wavelength of Lyman series is

A

`4//3`

B

`9//8`

C

`27//5`

D

`16//5`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = (hc)/(lambda), (1)/(lambda)= R[(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
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The ratio of wavelength for II line of Balmer series and I line of Lyman series is .

Obtain the ratio of the shortest wavelength of spectral line in the Lyman series to the longest wavelength of spectral line in the Balmer series.

Knowledge Check

  • The wavelength of Lyman series is

    A
    `(4)/(3 xx 10967) cm`
    B
    `(3)/(4 xx 10967) cm`1
    C
    `(4 xx 10967)/(3) cm`
    D
    `(3)/(4) xx 109767 cm`

  • The maximum wavelength of Lyman series is

    A
    `C/R`
    B
    `1/R^2`
    C
    `(4)/(3R)`
    D
    `(1)/(CR)`

  • The longest wavelength limit of Lyman series is

    A
    `4/(3 xx 109670)` cm
    B
    `3/(4 xx 109670)` cm
    C
    `(4 xx 109670)/3` cm
    D
    `(3 xx 109670)/4` cm

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    The ratio of wavelength of photon corresponding to the alpha -line of Lyman series in H-atom and beta - line of Balmer series in He^(+) is :

    The ratio of the longest and shortest wavelengths of the Lyman series is approximately

    The ratio of the largest to shortest wavelength in Lyman series of hydrogen spectra is

    The ratio of wavelength of 1st line of Balmer series and 2nd line of Lyman series is :

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