Home
Class 11
CHEMISTRY
Energy of an electron is givem by E = - ...

Energy of an electron is givem by `E = - 2.178 xx 10^-18 J ((Z^2)/(n^2))`. Wavelength of light required to excited an electron in an hydrogen atom from level `n = 1` to `n = 2` will be
`(h = 6.62 xx 10^-34 Js` and `c = 3.0 xx 10^8 ms^-1`).

A

`1.214 xx 10^(-7)` m

B

`2.816 xx 10^(-7)` m

C

`6.5 xx 10^(-7)` m

D

`8.5 xx 10^(-7)` m

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta E = (hc)/(lambda)= 2.178 xx 10^(-18) ((1)/(n_1^2)- (1)/(n_2^2))`
`(6.6256 xx 10^(-34) xx 3 xx 10^(8) )/(lambda) = 2.178xx 10^(-18) ((1)/(1^2)-(1)/(2^2))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV dE-BROGLIE.S AND HEISENBERG.S|4 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV QUANTUM MECHANICAL MODEL OF ATOM|3 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV H-SPECTRUM|7 Videos

  • STATES OF MATTER

    NARAYNA|Exercise A & R TYPE QUESTIONS|16 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Assertion- Reason|5 Videos

Similar Questions

Explore conceptually related problems

The ionisation energy of hydrogen atom is 1.312xx10^(6) J "mol"^(-1) . Calculate the energy required to excite an electron in a hydrogen atom from the ground state to the first excited state.

Energy of an electron is given by E= -2.178 xx 10^(-18)J ((z^(2))/(n^(2))) . The wavelength of light required to excite an electron in a hydrogen atom from level n=1 to n=2 will be ( h= 6.62 xx 10^(-34)Js, C= 3.0 xx 10^(8) ms^(-1) )

Knowledge Check

  • Energy of an electron is given by E = - 2.178 xx 10^-18 J ((Z^2)/(n^2)) . Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be (h = 6.62 xx 10^-34 Js and c = 3.0 xx 10^8 ms^-1 ).

    A
    `1.214 xx 10^-7 m`
    B
    `2.816 xx 10^-7 m`
    C
    `6.500 xx 10^-7 m`
    D
    `8.500 xx 10^-7 m`

  • Energy of an electron is given by E = -2.178 xx 10^(-18) J ((Z^(2))/(n^(2))) . Wavelength of light required to excite an electron in a hydrogen atom from level 1 to level 2 will be (h = 6.62 xx 10^(-34) Js and c = 3 xx 10^(8) ms^(-1))

    A
    `8.500 xx 10^(-7) m`
    B
    `1.214 xx 10^(-7) m`
    C
    `2.816 xx 10^(-7) m`
    D
    `6.500 xx 10^(-7) m`

  • Energy of an electron is given b yE= -2.178xx10^(-18)J((Z^(2))/(n^(2))) . Wavelength of light required to execite an electron in an hydrogen atom from level n = 1 t on= 2 will be: (h=6.62xx10^(-34) J s and c=3.0xx10^(8) ms^(-1))

    A
    `1.214xx10^(-7)m`
    B
    `2.816xx10^(-7)m`
    C
    `6.500xx10^(-7)m`
    D
    `8.500xx10^(-7)m`

    • Similar Questions

    Explore conceptually related problems

    the wavelength of light that must be absorbed to excite a hydrogen electron from level n = 1 to level n = 2 , will be (n = 6.625 xx 10^(-34) Js, C = 3 xx 10^8 ms^(-1))

    Based on the equation: Delta E = - 2.0 xx 10^(-18)J ((1)/(n_(2)^(2)) - (1)/(n_(1)^(2))) the wavelength of the light that must be absorbed to excite hydrogen electron from level n=1 to level n=2 will be: (h=6.625 xx 10^(-34) Js, C= 3 xx 10^(8) ms^(-1))

    Based on the equation : Delta E=-2.0xx10^(-18)J ((1)/(n_(2)^(2))-(1)/(n_(1)^(2))) the wavelength of the light that must be absorbed to excite hydrogen electron from level n = 1 to level n = 2 will be (h=6.625xx10^(-34) Js, C=3xx10^(8) ms^(-1))

    Energy of an electron in an excited hydrogen atom is -3.4eV . Its angualr momentum will be: h = 6.626 xx 10^(-34) J-s .

    The ionization enthalpy of hydrogen atom is 1.312xx10^6 "J mol"^(-1) . The energy required to excite the electron in the atom from n=1 to n=2 is

    Home
    Profile