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Find out the OH^(-) ion concentration in...

Find out the `OH^(-)` ion concentration in `100 mL` of `0.015 M HCl` is

A

`2.0xx10^(-9)M`

B

`6.7xx10^(-13) M`

C

`3xx10(-6)M`

D

`5xx10^(-12)M`

Text Solution

Verified by Experts

The correct Answer is:
B
`[OH^(-)]=(K_(w))/([H^(+)])=(1xx10^(-14)0.015)=6.7xx10^(-13)`
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