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I(2)+NaOH to NaI +NaOI...

`I_(2)+NaOH to NaI +NaOI`

A

`3I_(2)+5NaOH to NaIO_(3)+5NaI+3H_(2)O`

B

`2I_(2)+6NaOH to NaIO_(3)+5NaI+3H_(2)O`

C

`3I_(2)+6NaOH to NaIO_(3)+5NaI+3H_(2)O`

D

`4I_(2)+4NaOH to NaIO_(3)+4NaI+2H_(2)O`

Text Solution

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The correct Answer is:
B
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Balance the followin equation by oxidation number method: I_(2)+NaOH to NaIO_(3)+NaI+H_(2)O

Knowledge Check

  • For the reaction : I_(2)+NaOH toNaIO_(3)+NaI+H_(2)O . Identify the correct statements. (At.wt. of Na=23)

    A
    Reaction is an example of disproportionation
    B
    Equivalent weight of `I_(2)=(3)/(5)xx("mol. wt.of "I_(2))`
    C
    Eq. wt of NaOH in the rection is 6.66
    D
    Eq. wt of NaOH in the reaction is 48
  • Which of the following does not react with (I_(2)+NaOH) or NaOI :

    A
    `CH_(3)-CHO`
    B
    `CH_(3)-CH_(2)-CHO`
    C
    `CH_(3)-CH_(2)-OH`
    D
    `CH_(3)-underset(O)underset(||)C-CH_(3)`
  • (i) SiO_(2) + NaOH to ? (ii) SiO_(2) + HF to ? The products of (ii) & (i) respectively are

    A
    `H_(2) SiF_(6) , SiO_(4)^(4-)`
    B
    `SiF_(4) , Na_(2) SiO_(3)`
    C
    `Na_(2) SiO_(3) , SiF_(4)`
    D
    `Na_(2) SiO_(4) , H_(2) SiF_(6)`
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