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Calculate the amount of oxalic acid (eq....

Calculate the amount of oxalic acid (eq. wt. 63) required to prepare 500 ml of its 0.10N solution.

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To calculate the amount of oxalic acid required to prepare 500 ml of a 0.10N solution, we can follow these steps: ### Step 1: Understand the relationship between Normality and Equivalent Weight Normality (N) is defined as the number of equivalents of solute per liter of solution. For oxalic acid, the equivalent weight is given as 63 g/equiv. ### Step 2: Calculate the number of equivalents needed for 500 ml of a 0.10N solution Since we need to prepare 500 ml (which is 0.5 liters) of a 0.10N solution, we can calculate the number of equivalents required: \[ ...
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Knowledge Check

  • The amount of oxalic acid (eq. wt 63) required to preare 500 ml of its 0.10 N solution is

    A
    `0.315g`
    B
    `3.150g`
    C
    `6.300g`
    D
    `63.00g`
  • The amount of oxalic acid (mol. wt. 63) required to prepare 500 mL of its 0.10 N solution is

    A
    0.315 g
    B
    3.150 g
    C
    6.300 g
    D
    63.00 g
  • The amount of K_(2) Cr_(2)O_(7) ( eq. wt. 49.04) required to prepare 100 ml of its 0.05N solution is

    A
    2.9424 g
    B
    `0.4904g `
    C
    `1.4712g`
    D
    `0.245g`
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