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For which of the following electrolyte t...

For which of the following electrolyte the value of `Lambda_(m)` and `Lambda_(eq)` are same?

A

`Na_(2)SO_(4)`

B

`BaCl_(2)`

C

KCl

D

`Al_(2)(SO_(4))_(3)`

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To determine for which of the given electrolytes the values of molar conductance (Λ_m) and equivalent conductance (Λ_eq) are the same, we need to analyze the relationship between molarity and normality, and how they relate to the charge of the ions in the electrolyte. ### Step-by-Step Solution: 1. **Understand the Definitions**: - Molar conductance (Λ_m) is defined as the conductance of a solution containing one mole of electrolyte in a liter of solution. - Equivalent conductance (Λ_eq) is defined as the conductance of a solution containing one equivalent of electrolyte in a liter of solution. 2. **Formulas**: - The formulas for molar conductance and equivalent conductance are: \[ Λ_m = \frac{kappa \times 1000}{M} \] \[ Λ_eq = \frac{kappa \times 1000}{N} \] where \( kappa \) is the specific conductance, \( M \) is the molarity, and \( N \) is the normality. 3. **Condition for Equality**: - For Λ_m to equal Λ_eq, the condition is: \[ M = N \] - Normality (N) is related to molarity (M) by the equation: \[ N = M \times z \] where \( z \) is the number of equivalents per mole, which is determined by the charge of the ions. 4. **Analyze Each Electrolyte**: - **Na2SO4**: - Sodium (Na) has a charge of +1, and sulfate (SO4) has a charge of -2. - Total charge (z) = 2 (from SO4). - Therefore, \( N = M \times 2 \). Thus, \( Λ_m \neq Λ_eq \). - **BaCl2**: - Barium (Ba) has a charge of +2, and each chloride (Cl) has a charge of -1 (2 Cl). - Total charge (z) = 2 (from Ba). - Therefore, \( N = M \times 2 \). Thus, \( Λ_m \neq Λ_eq \). - **KCl**: - Potassium (K) has a charge of +1, and chloride (Cl) has a charge of -1. - Total charge (z) = 1 (from K). - Therefore, \( N = M \times 1 \). Thus, \( Λ_m = Λ_eq \). - **Al2(SO4)3**: - Aluminum (Al) has a charge of +3 (2 Al gives +6), and sulfate (SO4) has a charge of -2 (3 SO4 gives -6). - Total charge (z) = 6. - Therefore, \( N = M \times 6 \). Thus, \( Λ_m \neq Λ_eq \). 5. **Conclusion**: - The only electrolyte for which the values of Λ_m and Λ_eq are the same is **KCl**. ### Final Answer: The electrolyte for which the values of Λ_m and Λ_eq are the same is **KCl**.

To determine for which of the given electrolytes the values of molar conductance (Λ_m) and equivalent conductance (Λ_eq) are the same, we need to analyze the relationship between molarity and normality, and how they relate to the charge of the ions in the electrolyte. ### Step-by-Step Solution: 1. **Understand the Definitions**: - Molar conductance (Λ_m) is defined as the conductance of a solution containing one mole of electrolyte in a liter of solution. - Equivalent conductance (Λ_eq) is defined as the conductance of a solution containing one equivalent of electrolyte in a liter of solution. ...
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Knowledge Check

  • For which of the following electrolyte the value of .^ _(m) and ^^^_(eq) are same?

    A
    `Na_(2)SO_(4)`
    B
    `BaCl_(2)`
    C
    `KCl`
    D
    `Al_(2)(SO_(4))_(3)`.
  • Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) For which of the following electrolytic solution Lambda_(m) and Lambda_(e) are equal ?

    A
    `BaCl_(2)`
    B
    `KCl`
    C
    `Al_(2)(SO_(4))_(3)`
    D
    `CaCl_(2)`
  • If lambda_(m) denotes

    A
    `lambda_(m) prop T`
    B
    `lambda_(m) prop T^(-1)`
    C
    `lambda_(m) prop T`
    D
    `lambda_(m)` is independent on T
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