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The atomic numbers of vandium (V). Chrom...

The atomic numbers of vandium `(V)`. Chromium `(Cr)`, manganese `(Mn)` and iron (Fe) respectively 23, 24,25 and 26. Which one of these may be expected to have the higher second ionization enthalpy ?

A

V

B

Cr

C

Mn

D

Fe

Text Solution

Verified by Experts

The correct Answer is:
B
The second ionization energies are
`V=1414 kJ//mol`, `Cr=1592 kJ//mol`,
`Mn= 1509 kJ//mol`, `Fe = 1561 kJ//mol`
Cr has the highest second ionization energy because the second electron is to be removed from the half filled 3d subshell.
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Knowledge Check

  • The atomic numbers of vanadium (V) . Chromium (Cr) , managanese (Mn) and iron (Fe) respectively 23,24,25 and 26 . Which one of these may be expected to have the higer second ionization enthalpy?

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