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The partial pressure of Helium gas in th...

The partial pressure of Helium gas in the cylinder of volume 10L containing 0.4g of Helium, 1.6g of oxygen, 1.4g of nitrogen at `27^(0)C`

A

0.492 atm

B

49.2 atm

C

4.92 atm

D

0.0492 atm

Text Solution

Verified by Experts

Number of moles of `He = 0.4/4 = 0.1`
Number of moles of oxygen = `1.6/32 = 0.05`
Number of moles of nitrogen = `1.4/28 = 0.05`
Total moles in the 10.0 L cylinder at `27^@`C
`=0.1 + 0.05 + 0.05`
= 0.2 mol
`p_(T) = (nRT)/V = (0.2 xx 0.082 xx 300)/10 = 0.492` atm
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Calculate the total pressure in a 10.0 L cylinder which contains 0.4 g helium, 1.6g oxygen and 1.4 g nitrogen at 27^@ C

Knowledge Check

  • Calculate the total pressure in a 10.0 L cylinder which contains 0.4 g helium, 1.6g oxygen and 1.4 g nitrogen at 27^@ C

    A
    0.492 atm
    B
    49.2 atm
    C
    4.92 atm
    D
    0.0492 atm

  • At STP, 2 g of helium gas occupies a volume of

    A
    22.4L
    B
    11.2L
    C
    5.6L
    D
    2L

  • The partial pressure of ethane over a solution containing 6.56xx10^(-3) "g" of ethane is 1 bar. If the solution contains 5xx10^(-2)g of ethane, then what will be the partial pressure of gas ?

    A
    4.2 bar
    B
    7.6 bar
    C
    8.9 bar
    D
    9.8 bar

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