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The partial pressure of Helium gas in th...

The partial pressure of Helium gas in the cylinder of volume 10L containing 0.4g of Helium, 1.6g of oxygen, 1.4g of nitrogen at `27^(0)C`

A

0.492 atm

B

49.2 atm

C

4.92 atm

D

0.0492 atm

Text Solution

Verified by Experts

Number of moles of `He = 0.4/4 = 0.1`
Number of moles of oxygen = `1.6/32 = 0.05`
Number of moles of nitrogen = `1.4/28 = 0.05`
Total moles in the 10.0 L cylinder at `27^@`C
`=0.1 + 0.05 + 0.05`
= 0.2 mol
`p_(T) = (nRT)/V = (0.2 xx 0.082 xx 300)/10 = 0.492` atm
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