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people living at Mars ,instead of the usual definition of derivative `Df(x)` define a new kind of derivative `Df(x)` by the formula `Df(x)=lim_(h->0) (f^2(x+h)-f^2(x))/h` where `f^x` means `[f(x)]^2.` If `f(x)=xInx` then `Df(x)|_(x=e)` has the value (a) `e` (b) `2e` (c) `4e` (d) non

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Step by step text solution for people living at Mars ,instead of the usual definition of derivative Df(x) define a new kind of derivative Df(x) by the formula Df(x)=lim_(h->0) (f^2(x+h)-f^2(x))/h where f^x means [f(x)]^2. If f(x)=xInx then Df(x)|_(x=e) has the value (a) e (b) 2e (c) 4e (d) non by MATHS experts to help you in doubts & scoring excellent marks in Class 6 exams.

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Knowledge Check

  • Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D**F(x) by the formula D** (x) = lim_( h to 0) ( f^(2) ( x + h) - f^(2) (x))/( h) , where f^(2) (x) means [ f (x)]^(2) and if f(x) = x log x, then D** f(x) |_(x = e) has the value

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