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Objective : To construct a perpendicular...

Objective : To construct a perpendicular to a line segment from as external point using paper folding. Procedure : Draw a line segment AB and mark an external point P. Move B along BA till the fold passes through P and crease it along that line. The crease thus formed is the perpendicular to AB through the external point P.

Answer

Step by step text solution for Objective : To construct a perpendicular to a line segment from as external point using paper folding. Procedure : Draw a line segment AB and mark an external point P. Move B along BA till the fold passes through P and crease it along that line. The crease thus formed is the perpendicular to AB through the external point P. by MATHS experts to help you in doubts & scoring excellent marks in Class 9 exams.

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Objective : To construct a perpendicular bisector of a line segment using paper folding Procedure : Make a line segment on a paper by folding it and name it as PQ. Fold PQ in such a way that P falls on Q and thereby creating a creas RS. This line RS is the perpendicular bisector of PQ.

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Knowledge Check

  • If P(a,b) is the mid point of a line segment between the axes, then:

    A
    `(x)/(a)+(y)/(b)=1`
    B
    `(x)/(a)+(y)/(b)=2`
    C
    `(x)/(a)+(y)/(b)-1=0`
    D
    `(x)/(a)+(y)/(b)-2=0`

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    Objective : To find the mid - point of a line segment using paper folding Procedure : make a line segment on a paper by folding it and name it PQ. Fold the line segment PQ in such a way that P falls on Q and mark the point of intersection of the line segment and crease formed by folding the paper as M. M is the midpoint of PQ.

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    Objective : To locate the Orthocentre of a triangle using paper folding. Procedure : Using the above Activity with any two vertices of the triangle as external points, construct perpendiculars to opposite sides. The point of intersection of the perpendiculars is the Orthocentre of the given triangle.

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