Objective : To locate the circumcentre of a triangle using paper folding.
Procedure : Using Activity 12, find the perpendicular bisectors for any two sides of the given triangle. The meeting point of these is the circumcentre of the given triangle.

Objective : To locate the Orthocentre of a triangle using paper folding. Procedure : Using the above Activity with any two vertices of the triangle as external points, construct perpendiculars to opposite sides. The point of intersection of the perpendiculars is the Orthocentre of the given triangle.

Objective : To find the mid - point of a line segment using paper folding Procedure : make a line segment on a paper by folding it and name it PQ. Fold the line segment PQ in such a way that P falls on Q and mark the point of intersection of the line segment and crease formed by folding the paper as M. M is the midpoint of PQ.

Atempt any two of the following : Prove : In a triangle the angle bisector divides the side opposite to the angle in the ratio of the remaining sides.

In equilateral triangle ABC with interior point D, if the perpendicular distances from D to the sides of 4,5, and 6, respectively, are given, then find the area of A B Cdot

In equilateral triangle ABC with interior point D, if the perpendicular distances from D to the sides of 4,5, and 6, respectively, are given, then find the area of A B Cdot

Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.

If a vertex of a triangle is (1,1) , and the middle points of two sides passing through it are -2,3) and (5,2), then find the centroid and the incenter of the triangle.

If circumradius of triangle ABC is 4 cm, then prove that sum of perpendicular distances from circumcentre to the sides of triangle cannot exceed 6 cm

Objective : To construct a perpendicular bisector of a line segment using paper folding Procedure : Make a line segment on a paper by folding it and name it as PQ. Fold PQ in such a way that P falls on Q and thereby creating a creas RS. This line RS is the perpendicular bisector of PQ.