Home
Class 10
MATHS
ABCD is trapezium with AB || DC. The dia...

ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If `Delta AED ~ Delta BEC` . Prove that AD = BC .

Answer

Step by step text solution for ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If Delta AED ~ Delta BEC . Prove that AD = BC . by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GEOMETRY

    FULL MARKS|Exercise THINKING CORNER|2 Videos
  • GEOMETRY

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (MULTIPLE CHOICE QUESTIONS)|23 Videos
  • DEPARTMENTAL MODEL PAPER

    FULL MARKS|Exercise PART-IV|3 Videos
  • MENSURATION

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (iii)|8 Videos

Similar Questions

Explore conceptually related problems

ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB =46^(@) , find ∠OBC

In trapezium ABCD , side AB||DC Diagonals AC and BD intersect in O . If AB=20,DC=6, OB=15 . Find OD.

ABCD is a rectangle whose diagonals AC and BD intersect at O. If angleOAB= 46^(@) , find angleOBC .

squareABCD is a trapezium in which AB|| DC and its diagonals intersect each other at points O . Show that AO : BO = CO : DO.

In a quadrilateral ABCD, it is given that AB |\|CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD .

Attempt any Two of the following: In squareABCD ,seg AB ||seg CD . Diagonal AC and BD intersect each other at point P . Prove : (A(DeltaABP))/(A(DeltaCPD))=(AB^(2))/(CD^(2))

ABCD is a trapezium in which AB||DC and P, Q are points on AD and BC respectively, such that PQ||DC if PD = 18 cm, BQ = 35 cm and QC = 15 cm, find AD.

ABCD is a trapezium in which AB||DC and P,Q are points on AD and BC respectively, such that PQ||DC if PD=18 cm , BQ= 35 cm and QC= 15 cm, find AD.

ABCD is quadrilateral with AB parallel to DC. A line drawn parallel to AB meets AD at P and BC at Q. prove that (AP)/(PD) = (BQ)/(QC)

In squareABCD," side "BC|| side AD. Diagonal AC and diagonal BD intersects in point Q. If AQ=(1)/(3)AC, then show that DQ=(1)/(2)BQ.