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The molality of a solution containing 1....

The molality of a solution containing `1.8g` of glucose dissolved in 250g of water is ……………

A

`0.2m

B

`0.01m

C

`0.02m

D

`0.04m

Text Solution

Verified by Experts

The correct Answer is:
D
Molatity `= ("Number of moles of solute")/("Weight of solvent (in kg)") = (((1.8)/(180)))/( 0.25)= (0.01)/(0.25)=0.04 M`
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Knowledge Check

  • The molality of solution containing 1.8g of glucose dissolved in 250 g of water is _______

    A
    ` 0 . 2 ` M
    B
    ` 0 . 0 1 ` M
    C
    `0 . 0 2` M
    D
    `0 . 0 4 ` M

  • At 100^(@)C the vapour pressure of a solution containing 6.5 g of solute in 100 g water is 732 mm. If K=0.52, the boiling point of this solution will be:

    A
    `102^(@)C`
    B
    `100^(@)C`
    C
    `101^(@)C`
    D
    `100.52^(@)C`

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