What is the latent heat of fusion and latent heat of vapourisation of 10 g of ice and water respectively?

Options

A. 800 cal, 800 cal
B. 540 cal, 540 cal
C. 800 cal, 5400 cal
D. 540 cal, 800 cal

Explanation

To find the latent heat of fusion and the latent heat of vaporization for 10 g of ice and water respectively, we will follow these steps:

### Step 1: Understand the Definitions
- **Latent Heat of Fusion**: This is the amount of heat energy required to convert a unit mass of solid into liquid at constant temperature. For water, the latent heat of fusion is approximately **334 J/g**.
- **Latent Heat of Vaporization**: This is the amount of heat energy required to convert a unit mass of liquid into vapor at constant temperature. For water, the latent heat of vaporization is approximately **2260 J/g**.

### Step 2: Calculate the Latent Heat of Fusion for 10 g of Ice
To calculate the latent heat of fusion for 10 g of ice, we use the formula:
\[ \text{Latent Heat of Fusion} = \text{mass} \times \text{latent heat of fusion per gram} \]
Substituting the values:
\[ \text{Latent Heat of Fusion} = 10 \, \text{g} \times 334 \, \text{J/g} = 3340 \, \text{J} \]

### Step 3: Calculate the Latent Heat of Vaporization for 10 g of Water
To calculate the latent heat of vaporization for 10 g of water, we use the formula:
\[ \text{Latent Heat of Vaporization} = \text{mass} \times \text{latent heat of vaporization per gram} \]
Substituting the values:
\[ \text{Latent Heat of Vaporization} = 10 \, \text{g} \times 2260 \, \text{J/g} = 22600 \, \text{J} \]

### Final Answer
- The latent heat of fusion for 10 g of ice is **3340 J**.
- The latent heat of vaporization for 10 g of water is **22600 J**.

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