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A sample of wooden artifact is found to ...

A sample of wooden artifact is found to undergo 9 disintegration per minute per gram of carbon. What is the approximate age of the artifact? The half life of `._(6)^(14)C` is 5730 years and radioactivity of wood recently cut is 15 disintegrations per minute per gram of carbon.

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A sample of wooden aircrafts is found to undergo 9 dp m g^(-1) of .^(14)C . What is appoximate age of aircraffts? The half line of ._(6)^(14)C is 5730 year and rate of disintergration of wood recently cut down is 15 dp m g^(-1) do ._(6)^(14)C ?

A piece of ancient wood shows an activity of 3.9 disintergration per sec. per gram of .^(14)C . Calculate the age of the wood. T_(1//2) of .^(14) C=5570 years. Activity of fresh .^(14)C=15.6 disinteration per second per gram.

Knowledge Check

  • The quantity of .^(14)C as well as that of .^(14)CO_(2) present in the atmosphere remains constant. The concentration of .^(14)C in all living organisms remains almost constant during their life time. After their death, .^(14)C is not taken up by them but the content of .^(14)C assimilated begins to decay by emitting beta- particles, with half-life period of 5568 years. The decay rate at the time of death of plant is 16.1 counts per minute per gram of carbon. Hence, by measuring the decay rate of the dead matter, the age of matter can be calculated , e.g. if decay rate of sample of wood is found to be N distengrations per minute per gram of carbon after t years, then N=N_(0)e^(-lambda t) where lambda= disntegration constant and N_(0)= number of disntegrations per minute per gram when the plant had just died. The basis for carbon - 14 dating method is that the

    A
    `C-14` fraction is same in all objects
    B
    `C-14` is highly unstable and is readily lost from the objects
    C
    ratio of `.^(14)C` to `.^(12)C` in our atmosphere has always been constant
    D
    living tissue will not absorb `C-14` but will absorb `C-12` from their sources of carbon

  • The quantity of .^(14)C as well as that of .^(14)CO_(2) present in the atmosphere remains constant. The concentration of .^(14)C in all living organisms remains almost constant during their life time. After their death, .^(14)C is not taken up by them but the content of .^(14)C assimilated begins to decay by emitting beta- particles, with half-life period of 5568 years. The decay rate at the time of death of plant is 16.1 counts per minute per gram of carbon. Hence, by measuring the decay rate of the dead matter, the age of matter can be calculated , e.g. if decay rate of sample of wood is found to be N distengrations per minute per gram of carbon after t years, then N=N_(0)e^(-lambda t) where lambda= disntegration constant and N_(0)= number of disntegrations per minute per gram when the plant had just died. .^(14)C is present in environmental because of

    A
    artifical transmutation
    B
    cosmic neutron bombardment of nitrogen
    C
    it being a part of radioactive series happening naturally
    D
    `.^(12)C` when gets bombarded with neutrons, transmutes to `.^(14)C` in environment

  • The quantity of .^(14)C as well as that of .^(14)CO_(2) present in the atmosphere remains constant. The concentration of .^(14)C in all living organisms remains almost constant during their life time. After their death, .^(14)C is not taken up by them but the content of .^(14)C assimilated begins to decay by emitting beta- particles, with half-life period of 5568 years. The decay rate at the time of death of plant is 16.1 counts per minute per gram of carbon. Hence, by measuring the decay rate of the dead matter, the age of matter can be calculated , e.g. if decay rate of sample of wood is found to be N distengrations per minute per gram of carbon after t years, then N=N_(0)e^(-lambda t) where lambda= disntegration constant and N_(0)= number of disntegrations per minute per gram when the plant had just died. .^(14)C is

    A
    an artificial radioactive isotope
    B
    a natural radioactive isotope
    C
    a natural non-radioactive isotope
    D
    an artifical non-radioactive isotope

    • Similar Questions

    Explore conceptually related problems

    A piece of wood form the ruins of an nuclei an ancient building was found to have a .^(14)C activity of 12 disintegrations per minute per gram of its carbon content. The .^(14)C activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, form which the wooden sample came, die? Given half-life of .^(14)C is 5760yers .

    The normal activity of living carbon -containing matter is found to be about 15 decay per minute for every gram of carbon. This activity arises form the small proportion of radioactive ._6C^(14) present with the ordinary ._6C^(12) isotope. When the organism is dead, its interaction with the atmosphare which maintains the above equilibrium activity, ceases and its activity begins to drop. form the known half life (=5730years) of ._6C^(14) , and the measured activity, the age of the specimen can be approximately estimated. This is the principle of ._6C^(14) dating used in archaeology. Suppose a spacimen form Mohenjodaro gives an activity of 9 decays per minute per gram of carbon. Estimate the approximate age of the Indus Vally Civilization.

    The quantity of .^(14)C as well as that of .^(14)CO_(2) present in the atmosphere remains constant. The concentration of .^(14)C in all living organisms remains almost constant during their life time. After their death, .^(14)C is not taken up by them but the content of .^(14)C assimilated begins to decay by emitting beta- particles, with half-life period of 5568 years. The decay rate at the time of death of plant is 16.1 counts per minute per gram of carbon. Hence, by measuring the decay rate of the dead matter, the age of matter can be calculated , e.g. if decay rate of sample of wood is found to be N distengrations per minute per gram of carbon after t years, then N=N_(0)e^(-lambda t) where lambda= disntegration constant and N_(0)= number of disntegrations per minute per gram when the plant had just died. In a dead plant, the decay rate will be

    Ra^(226) has half life of 1600 years. The number of disintegration per second per gram is

    A woord specimen from an archeological centre shows a ._(6)^(14)C activity of 5.0 counts/min/gm of carbon. What is the age of the specimen ( t_(1//2) " for " ._(6)^(14)C is 5000 years) and a freshly cut wood gives 15 counts/min/g of carbon

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