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Uranium (""(92)U""^(238)) decayed to ""(...

Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)`
`t""_(1//2)of U""^(238)=4.5xx10""^(9)` years
x and y in above decay series are

A

6,8

B

8,6

C

8,8

D

6,6

Text Solution

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The correct Answer is:
b
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Knowledge Check

  • Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years The analysis of a rock shows the relative number of U""^(238) and Pb""^(206) atoms (Pb/U=0.25). The age of rock will be

    A
    `2.303/0.693xx4.5xx10""^(9)log1.25`
    B
    `2.303/0.693xx4.5xx10""^(9)log0.25`
    C
    `2.303/0.693xx4.5xx10""^(9)log4`
    D
    `2.303/(4.5xx10""^(9))xx0.693log4`
  • Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years A sample of rock from South America contains equal number of atoms of U""^(238) and Pb""^(""^(206) . The age of the rock will be

    A
    `4.5xx10""^(9)years`
    B
    ?
    C
    `13.5xx10""^(9)years`
    D
    `2.25xx10""^(9)years`
  • Uranium ._(92)U^(238) decayed to ._(82)Pb^(206) . They decay process is ._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206)) t_(1//2) of U^(238) = 4.5 xx 10^(9) years The analysis of a rock shows the relative number of U^(238) and Pb^(206) atoms (Pb//U = 0.25) The age of rock will be

    A
    `(2.303)/(0.693) xx 4.5 xx 10^(9) "log" 1.25`
    B
    `(2.303)/(0.693) xx 4.5 xx 10^(9) "log" 0.25`
    C
    `(2.303)/(0.693) xx 4.5 xx 10^(9) "log" 4`
    D
    `(2.303)/(0.693) xx 4.5 xx 10^(9) "log" 1.25`
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