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Radioactive decay follows first-order ki...

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are `tau = 1// lambda` and `t_(1//2) = 0.693//lambda`. Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after `n` half lives of radioactive elements can be calculated using the relation:
`N = N_(0) ((1)/(2))^(n)`
Which `"is"//"are"` true about the decay cosntant? a)Unit of `lambda` is `"time"^(-1)` b)`lambda` is independent of temperature c)`lambda` depends on the initial amount of element taken. d)`lambda` depends on the nature of radioactive element.

A

Unit of `lambda` is `"time"^(-1)`

B

`lambda` is independent of temperature

C

`lambda` depends on initial amount of element taken

D

`lambda` depend on the nature of radioactive element

Text Solution

Verified by Experts

The correct Answer is:
a,d
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Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Amount of radioactive elements (activity) decreases with passage of time as

Knowledge Check

  • Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Select the correct relation.

    A
    `t_(1//2) = (0.693)/(lambda)`
    B
    `tau = (1)/(lambda)`
    C
    `tau = 1.44 xx t_(1//2)`
    D
    `tau = (t_(1//2))/(0.693)`
  • Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) The rate of radioactive decay is

    A
    Independent of lime
    B
    Independent of temperature
    C
    Dependent on catalyst
    D
    Dependent on the amount of elementsd not yet decayed
  • Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Half life of .^(60)Co is 5.3 years, the time taken for 99.9% decay will be

    A
    0.53 years
    B
    53 years
    C
    530 years
    D
    5300 years
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