A body of mass x g is moving with a velocity of 100m/s. It de Broglie wavelength is `6.62xx10^(-35)m`. Hence x is `(h=6.62xx10^(-34)J-s)`

Options

A. 0.25kg
B. 0.15 kg
C. 0.2 kg
D. 0.1 kg

Answer

D

Explanation

Accordin to de-Broglie's equation,
`lamda=h/(mv)`
Given `lamda=6.62xx10^(-35)m`
`v=100ms^(-1)`
`h=6.62xx10^(-34)Js`
and `m=x` kg
`:.6.62xx10^(-35)=(6.62xx10^(-34))/(x xx 100)`
`impliesx=0.1 kg`