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A body of mass x g is moving with a velo...

A body of mass x g is moving with a velocity of 100m/s. It de Broglie wavelength is `6.62xx10^(-35)m`. Hence x is `(h=6.62xx10^(-34)J-s)`

A

0.25kg

B

0.15 kg

C

0.2 kg

D

0.1 kg

Text Solution

Verified by Experts

The correct Answer is:
D

Accordin to de-Broglie's equation,
`lamda=h/(mv)`
Given `lamda=6.62xx10^(-35)m`
`v=100ms^(-1)`
`h=6.62xx10^(-34)Js`
and `m=x` kg
`:.6.62xx10^(-35)=(6.62xx10^(-34))/(x xx 100)`
`impliesx=0.1 kg`
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Knowledge Check

  • A body of mass x kg is moving with a velocity of 100 m/s.Its de Broglie wavelength is 6.62xx10^(-35) m . Hencex is [h=6.2xx10^(-34)Js]

    A
    `0.25 kg`
    B
    `0.15 kg`
    C
    `0.2 kg`
    D
    `0.1 kg`
  • A body of mass x kg is moving with a velocity of 100 ms^(-1). Its de-Broglie wavelength is 6.62 xx 10^(-35) m. Hence x is (h = 6.62 xx 10^(-34) Js)

    A
    0.1 kg
    B
    0.25 kg
    C
    0.15 kg
    D
    0.2 kg.
  • The momentum of a particle having a de-Broglie wavelenth of 10^(-17) m is ( h=6.625xx10^(-34)Js )

    A
    `6.625xx10^(-17)kgms^(-1)`
    B
    `3.3125xx10^(-7)kgms^(-1)`
    C
    `13.25xx10^(-17)kgm^(-1)`
    D
    `26.5xx10^(-7)kgms^(-1)`
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