If mu(0) is permeability of free space a...

If `mu_(0)` is permeability of free space and `epsilon_(0)` is permittivity of free space , the speed of light in vacuum is given by

`sqrt((1)/(mu_(0)epsilon_(0)))`

`sqrt((epsilon_(0))/(mu_(0)))`

`sqrt(mu_(0)epsilon_(0))`

`sqrt((mu_(0))/(epsilon_(0)))`

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The correct Answer is:

The velocity of light `c=(1)/(sqrt(mu_(0)epsilon_(0)))`

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