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What are the values of 'a' for which the...

What are the values of 'a' for which the function `f(x)=a^(x)` is :
(i) increasing
(ii) decreasing in R?

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The correct Answer is:
To determine the values of 'a' for which the function \( f(x) = a^x \) is increasing or decreasing in \( \mathbb{R} \), we need to analyze the derivative of the function. ### Step 1: Differentiate the function The first step is to find the derivative of the function \( f(x) = a^x \). \[ f'(x) = \frac{d}{dx}(a^x) = a^x \ln(a) \] ### Step 2: Determine when the function is increasing A function is increasing when its derivative is greater than zero: \[ f'(x) > 0 \implies a^x \ln(a) > 0 \] Since \( a^x \) is always positive for any real \( x \) (as long as \( a > 0 \)), we only need to consider \( \ln(a) \): \[ \ln(a) > 0 \] This inequality holds when: \[ a > 1 \] ### Step 3: Determine when the function is decreasing A function is decreasing when its derivative is less than zero: \[ f'(x) < 0 \implies a^x \ln(a) < 0 \] Again, since \( a^x \) is always positive for \( a > 0 \), we need: \[ \ln(a) < 0 \] This inequality holds when: \[ 0 < a < 1 \] ### Final Results - The function \( f(x) = a^x \) is **increasing** for \( a > 1 \). - The function \( f(x) = a^x \) is **decreasing** for \( 0 < a < 1 \). ### Summary of Values - **Increasing:** \( a \in (1, \infty) \) - **Decreasing:** \( a \in (0, 1) \)
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Knowledge Check

  • The interval on which the function f(x)=2x^(2)-3x is increasing or decreasing in :

    A
    `[-oo,(3)/(4)]`
    B
    `[3,oo]`
    C
    `[(3)/(4),3]`
    D
    `[(3)/(4),oo]`
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