Home
Class 12
MATHS
Draw a rough sketch of the curves y=sin ...

Draw a rough sketch of the curves y=sin x and y= cos x as x varies from 0 to `pi/2` and find the area of the region enclosed between them and the x-axis

Text Solution

Verified by Experts

The correct Answer is:
`(2-sqrt2)` sq. units.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATIONS OF THE INTEGRALS

    MODERN PUBLICATION|Exercise OBJECTIVE TYPE QUESTIONS|20 Videos

  • APPLICATIONS OF THE INTEGRALS

    MODERN PUBLICATION|Exercise OBJECTIVE TYPE QUESTIONS -FILL IN THE BLANKS|5 Videos

  • APPLICATIONS OF THE INTEGRALS

    MODERN PUBLICATION|Exercise EXERCISE 8 (A)|28 Videos

  • APPLICATIONS OF DERIVATIVES

    MODERN PUBLICATION|Exercise CHAPTER TEST (1)|12 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos

Similar Questions

Explore conceptually related problems

Draw a rough sketch of the curves y=sinx and y=cosx as x varies from 0 to pi/2 . Find the area of the region enclosed by the curves and the y-axis.

Draw a rough sketch of the curves y=sin x varies from 0 to (pi)/(2) and find the area of the region enclosed by them and x-axis

Knowledge Check

  • Area of the region enclosed between the curve x =1-y^(2) and the Y-axis is

    A
    `(5)/(3)`
    B
    `(4)/(3)`
    C
    `(2)/(3)`
    D
    `(1)/(3)`

    • Similar Questions

    Explore conceptually related problems

    Find the area of the region enclosed between curves y = |x-1| and y=3-|x| .

    Draw the rough sketch of the curve y=x^(4)-x^(2) .

    Find the area of the region enclosed by the given curves y=cos x,y=1-(2x)/(pi)

    Find the area of the region enclosed by the curves y=x log x and y=2x-2x^(2).

    Find the area of the region enclosed by curves y=sin x and y=cos x as x varies 0 to (pi)/(2) with x -axis

    Draw a rough sketch of the curves y^(2)=x+1 and y^(2)=-x+1 and find the area enclosed between them,

    Make a rough sketch of the graph of the function y =2 sin x, 0 le x le (pi)/(2) and determine the area enclosed between the curve, the x-axis and the line x = (pi)/(2).

    Home
    Profile