Calculate the emf of the following cell at `298K`:
`Fe(s)|Fe^(2+)(0.001M)||H^+(1M)|H_2(g)(1"bar"),Pt(s)` (Given`E_("Cell")^@=+0.44V)`

Explanation

To calculate the emf of the given electrochemical cell at 298K, we will follow these steps:

### Step 1: Identify the half-reactions
In the given cell:
- At the anode (oxidation), iron is oxidized:
\[ \text{Fe(s)} \rightarrow \text{Fe}^{2+} + 2e^- \]
...