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A 4% solution (w/w) of sucrose (M 342 g ...

A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a freezing point of 271.15K Calculate the freezing point of 5% glucose (M= 180 g `mol^(-1)`) in water.
(Given: Freezing point of pure water 273.15 K)

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To solve the problem, we need to calculate the freezing point of a 5% glucose solution in water, given that a 4% sucrose solution has a freezing point of 271.15 K. We will use the freezing point depression formula: \[ \Delta T_f = K_f \cdot i \cdot m \] Where: - \(\Delta T_f\) = depression in freezing point ...
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A 5% solution (w/W) of cane sugar (molar mass = 342 g mol^(-1) ) has freezing point 271 K. What will be the freezing point of 5% glucose (molar mass = 18 g mol^(-1) ) in water if freezing point of pure water is 273.15 K ?

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

(a) A 10% solution (by mass) of sucrose in water has freezing point of 269.15K. Calculate the freezing point of 10% glucose in water, if the freezing point of pure water is 273.15K. Given: (molar mass of sucrose=342 g mol^(-1) ) (Mola mass of glucose =180g mol^(-1) ) (b) Define the following terms: (i) Molality (m) (ii) Abnormal molar mass

A 10% solution (by mass) pf sicrose in water has freezing point of 269.15 K. Calculate freezing point of 10% glucose in water, if freezing point of pure is 273.15 K (Given molar mass of sucrose= 342 g mol^(-1) , Molar mass of glucose =180 g mol^(-1) ).

XII BOARDS PREVIOUS YEAR-XII BOARDS-SECTION-C
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