Home
Class 12
CHEMISTRY
A 4% solution (w/w) of sucrose (M 342 g ...

A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a freezing point of 271.15K Calculate the freezing point of 5% glucose (M= 180 g `mol^(-1)`) in water.
(Given: Freezing point of pure water 273.15 K)

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the freezing point of a 5% glucose solution in water, given that a 4% sucrose solution has a freezing point of 271.15 K. We will use the freezing point depression formula: \[ \Delta T_f = K_f \cdot i \cdot m \] Where: - \(\Delta T_f\) = depression in freezing point ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-D|12 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise CHEMISTRY (Theory) [SET - I]|34 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-B|22 Videos
  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION: D|1 Videos

Similar Questions

Explore conceptually related problems

A 4% solution (w/w) of sucrose (M = 342 g "mol"^(-1) ) in water has a freezing point of 271.15 K. Calculate the freezing point of 5% glucose (M = 180 g "mol"^(-1) ) in water. (Given : Freezing point of pure water = 273.15 K)

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose in water if freezing point of pure wateris 273.15 K.

Knowledge Check

  • A 5% solution (w/W) of cane sugar (molar mass = 342 g mol^(-1) ) has freezing point 271 K. What will be the freezing point of 5% glucose (molar mass = 18 g mol^(-1) ) in water if freezing point of pure water is 273.15 K ?

    A
    273.07 K
    B
    269.07 K
    C
    273.15 K
    D
    260.09 K
  • Similar Questions

    Explore conceptually related problems

    A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose in water if freezing point of pure water is 273.15 K.

    A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

    A 10% solution (by mass) of sucrose in water has freezing point of 269.15 K. Calculate the freezing point of 10% glucose solution in water, if freezing point of pure water is 273.15 K. Given : (Molar mass of sucrose = "342 g mol"^(-1) , molar mass of glucose ="180 g mol"^(-1) ).

    A 10% solution (by mass) of sucrose in water has a freezing point of 269.15 K. Calculate the freezing point of 10% glucose in water if the freezing point of pure water is 273.15 K. [Given : Molar mass of sucrose = 342 g "mol"^(-1) , Molar mass of glucose = 180 g "mol"^(-1) ]

    A 10% solution (by mass) of sucrose in water has freezing point of 269.15 K. Calculate the freezing point of 10% glucose in water, if freezing point of pure water is 273.15 K. [Given : Molar mass of sucrose = 342 g "mol"^(-1) , Molar mass of glucose = 180 g "mol"^(-1) ]

    (a) A 10% solution (by mass) of sucrose in water has freezing point of 269.15K. Calculate the freezing point of 10% glucose in water, if the freezing point of pure water is 273.15K. Given: (molar mass of sucrose=342 g mol^(-1) ) (Mola mass of glucose =180g mol^(-1) ) (b) Define the following terms: (i) Molality (m) (ii) Abnormal molar mass

    A 10% solution (by mass) pf sicrose in water has freezing point of 269.15 K. Calculate freezing point of 10% glucose in water, if freezing point of pure is 273.15 K (Given molar mass of sucrose= 342 g mol^(-1) , Molar mass of glucose =180 g mol^(-1) ).