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When compound (A) is treated with conc. ...

When compound (A) is treated with conc. `H_(2)SO_(4)`, a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D).
Gas (B) may be :

A

`Cl_(2)`

B

`Br_(2)`

C

`I_(2)`

D

`NO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`underset((A))(NaNO_(3))+H_(2)SO_(4) to NaHSO_(4)+HNO_(3)`
`2HNO_(3) to H_(2)O+ underset((B))(2NO_(2))uarr+[O]`
`2C_(6)H_(5)NHC_(6)H_(5)+[O] to (C_(6)H_(5))_(2)underset("blue ring"(D))(N-N(C_(6)H_(5))_(2))+H_(2)O`
This testing also given by various oxidising agent like `CrO_(4)^(2-), Cr_(2)O_(7)^(2-),ClO_(3)^(-)` etc.
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When compound (A) is treated with conc. H_(2)SO_(4) , a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D). Compound (D) has formula :

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Knowledge Check

  • When Kbr is treated with concentrated H_(2)SO_(4) reddich brown gas evolved, gas is

    A
    Mixture of bromine and `HBr`
    B
    `HBr`
    C
    Bromine
    D
    None of these
  • When formic acid is treated with conc. H_(2)SO_(4) , the gas evolved is :

    A
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    B
    `SO_(2)`
    C
    `CO`
    D
    `CO_(2)`
  • When formic acid or oxalic acid is treated with conc. H_(2)SO_(4) , the gas evolved is

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    CO
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