Home
Class 12
CHEMISTRY
In brown ring complex, if number of ambi...

In brown ring complex, if number of ambidentate is/are "a" and oxidation state of iron is/are "b" then a+b=?

Text Solution

Verified by Experts

The correct Answer is:
5

`a=0 " " H_(2)O,NO^(+)` are not ambidentate ligand
`b=1 " " Fe^(+1)`
`a+b=1`
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Paragraph For Questions|3 Videos
  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Matching List Type|1 Videos
  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Part-IV : Practice Test-18|1 Videos
  • QUALITATIVE ANALYSIS

    RESONANCE|Exercise INORGANIC CHMISTRY(Qualitative analysis)|35 Videos
  • QUALITATIVE ANALYSIS PART 1

    RESONANCE|Exercise A.L.P|39 Videos

Similar Questions

Explore conceptually related problems

Most stable oxidation state of iron is

In haemoglobin the iron is in oxidation state of

Oxidation state of iron in Fe(CO)_(4) is

What is the oxidation state of iron in haemoglobin ?