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In brown ring complex, if number of ambi...

In brown ring complex, if number of ambidentate is/are "a" and oxidation state of iron is/are "b" then a+b=?

Text Solution

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The correct Answer is:
5
`a=0 " " H_(2)O,NO^(+)` are not ambidentate ligand
`b=1 " " Fe^(+1)`
`a+b=1`
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Knowledge Check

  • Most stable oxidation state of iron is

    A
    `+ 2`
    B
    `+3`
    C
    `-2`
    D
    `-3`

  • Oxidation state of iron in Haemoglobin is

    A
    `+2`
    B
    `+3`
    C
    `0`
    D
    `-2`

  • Oxidation state if iron in ferric is

    A
    `+2`
    B
    `+5`
    C
    `+3`
    D
    `+6`

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