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1 g of complex [Cr(H(2)O)(5)Cl]Cl(2).H(2...

1 g of complex `[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O` was passed through a cation exchanger to produce HCl. The acid liberated was diluted to 1 litre. What will be the molarity of acid solution [Molecular weight of complex=266.5]?

Text Solution

Verified by Experts

The correct Answer is:
0.0075
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1 g of the complex [Cr(H_(2)O)_(5)Cl]Cl_(2). H_(2)O was passed through a cation exchanger to produce HCl. The acid liberated was diluted to 1 litre. What is the normality of this acid solution ?

A solution containing 1 go of the complex [Cr(H_(2)O)_(5)CI]CI_(2)H_(2)O was passed through a cation exchanger The acid liberated was made up to 1 litre Calculate the strength of acid solution ( Aw of Cr=52 and Mw of complex = 266.5 g mo1^(-1) .

Knowledge Check

  • 1 g of a complex [Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2O (mol. Wt. 266.5) was passed through a cation exchanger to produce HCl. The acid liberated was diluted to 1 litre. The normality of this acid solution is

    A
    `5xx10^(-3)N`
    B
    `7.5xx10^(-3)N`
    C
    `7.5xx10^(-2)N`
    D
    `7.5xx10^(-1)N`

  • A solution containing 0.319 gm of complex CrCl_(3).6H_(2)O was passed through cation exchanger and the solution given out was neturalised by 28.5 ml of 0.125 M NaOH . The correct formula of the complex will be : [Molecular weight of complex = 266.5]

    A
    `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
    B
    `[CrCl(H_(2)O)_(6)]Cl_(3)`
    C
    `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
    D
    all are correct

  • A solution containing 0.319 g of complex CrCl_(3).6H_(2)O was passed through cation exchanger and the solution given out was neutralised by 28.5 ml of 0.125 m NaOH. The correct formula of the complex will be: [ molecular weight of complex =266.5]

    A
    `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
    B
    `[Cr(H_(2)O)_(6)]Cl_(3)`
    C
    `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
    D
    All are correct

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    From the experimental facts given below determine the correct structure of solid CrCI_(3) .6H_(2)O Solution containing 0.2665g of CrCI_(3)6H_(2) O was passed throuhg cation exchange resin in acid form The acid liberated was found to react completely with 30mL of 0.10M Na OH ("Molecular mass of" CrCI_(3).6H_(2)O=266.5) .

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    A solution containing 0.319 g of CrCl_(3).6 H_(2)O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of 0.125 M NaOH. Determine correct formula of the complex [Mol. Wt. of the complex = 266.5]

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