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Chromium hexacabonyl is an octahedral co...

Chromium hexacabonyl is an octahedral compound involving :

A

`sp^(3)d^(2)`

B

`dsp^(2)`

C

`d^(2)sp^(3)`

D

`dsp^(3)`

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The correct Answer is:
To determine the characteristics of chromium hexacarbonyl, we can break down the problem into several steps: ### Step 1: Identify the Compound Chromium hexacarbonyl is denoted as Cr(CO)₆. It consists of a chromium ion coordinated with six carbonyl (CO) ligands. **Hint:** Look for the central metal ion and the ligands attached to it. ### Step 2: Determine the Oxidation State of Chromium In chromium hexacarbonyl, carbonyl (CO) is a neutral ligand, which means it does not contribute any charge. Therefore, the oxidation state of chromium in this complex is 0. **Hint:** Remember that neutral ligands do not affect the oxidation state of the central metal. ### Step 3: Write the Electron Configuration of Chromium The electron configuration of chromium (Cr) in its elemental form is [Ar] 4s² 3d⁴. Since chromium is in the zero oxidation state, it retains all its electrons. **Hint:** Use the periodic table to find the electron configuration of chromium. ### Step 4: Consider the Ligand Field Theory Carbonyl is a strong field ligand, which means it can cause pairing of electrons in the d-orbitals. In the presence of six carbonyl ligands, the 3d electrons will pair up. **Hint:** Strong field ligands can lead to the pairing of electrons in the lower energy d-orbitals. ### Step 5: Determine the Hybridization With six ligands surrounding the chromium ion, the hybridization can be determined. The pairing of the 3d electrons and the involvement of the 4s and 4p orbitals leads to a hybridization of D₂sp³. **Hint:** For octahedral complexes, the hybridization can often be determined by the number of ligands and the orbitals involved. ### Step 6: Identify the Geometry of the Compound Since chromium hexacarbonyl has a D₂sp³ hybridization, it adopts an octahedral geometry. **Hint:** The arrangement of ligands around the central metal ion can help you visualize the geometry. ### Final Answer Chromium hexacarbonyl (Cr(CO)₆) is an octahedral compound involving D₂sp³ hybridization. ---
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Knowledge Check

  • Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Select the correct statement.

    A
    Both `[NiCl_(2)(PPh_(3))_(2)]` and its analogous Pd(II) show geometrical isomerism.
    B
    `[CoBrCl(en)_(2)]` will show geometrical isomerism but is chiral compound.
    C
    `cis-[Co(NH_(3))_(4)Br_(2)]^(+)` can exist as enantiomer
    D
    A complex of palladium (II) with two chloride ions and two thiocyanate ions will show linkage as well as geometrical isomerism.
  • Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which one of the following statements is false ?

    A
    `[cis-Pt(NH_(3))_(2)Cl_(2)]` will have some dipole moment
    B
    `[cis-Pt(NH_(3))_(2)Cl_(2)]` will show geometrical as well as optical isomerism.
    C
    `cis-[CrCl_(2)("ox")_(2)]` is a chiral molecules.
    D
    (a) and (b) both
  • Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which one of the following statements is false ?

    A
    `[cis-Pt(NH_(3))_(2)Cl_(2)]` will have some dipole moment
    B
    `[cis-Pt(NH_(3))_(2)Cl_(2)]` will show geometrical as well as optical isomerism.
    C
    `cis-[CrCl_(2)("ox")_(2)]` is a chiral molecules.
    D
    (a) and (b) both
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