`CH_(3)CH_(2)CH(CHO)CH_(2)CH_(3) and CH_(3)CH(CHO) CH_(2)CH_(2)CH_(3)` are :-

Options

A. Chain isomer
B. Position isomer
C. Metamerism
D. Functional isomer

Answer

To determine the type of isomerism exhibited by the compounds \( CH_3CH_2CH(CHO)CH_2CH_3 \) and \( CH_3CH(CHO)CH_2CH_2CH_3 \), we can follow these steps:

### Step 1: Draw the Structures
1. For the first compound \( CH_3CH_2CH(CHO)CH_2CH_3 \):
- Start with the longest carbon chain which has 5 carbon atoms.
- The aldehyde group (CHO) is attached to the third carbon.
- The structure can be represented as:
```
CH3-CH2-CH-CH2-CH3
|
CHO
```

2. For the second compound \( CH_3CH(CHO)CH_2CH_2CH_3 \):
- Again, identify the longest carbon chain which also has 5 carbon atoms.
- The aldehyde group (CHO) is attached to the second carbon.
- The structure can be represented as:
```
CH3-CH-CH2-CH2-CH3
|
CHO
```

### Step 2: Identify the Parent Chain
- In both structures, the longest continuous chain of carbon atoms is 5.
- The first compound has the aldehyde group on the third carbon, while the second compound has it on the second carbon.

### Step 3: Analyze the Differences
- The key difference between the two compounds is the position of the aldehyde group relative to the carbon chain.
- The first compound has the aldehyde group on the third carbon, while the second compound has it on the second carbon.

### Step 4: Classify the Isomerism
- Since the two compounds have the same molecular formula but differ in the arrangement of the carbon skeleton (specifically the position of the functional group), they are classified as **chain isomers**.

### Conclusion
Thus, the two compounds \( CH_3CH_2CH(CHO)CH_2CH_3 \) and \( CH_3CH(CHO)CH_2CH_2CH_3 \) are **chain isomers**.

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