5 mol of an ideal gas expand reversibly from a volume of `8 dm^(3)` to `80 dm^(3)` at an temperature of `27^(@)C`. Calculate the change in entropy.

Explanation

For isothermal reversible process `Delta S=2.303 "nR log" (V_(2))/(V_(1))=2.303xx5molxx8.314"J/mol K log"(80)/(8)=95.73JK^(-1)`