Four moles of an ideal gas expand isothermally from 1 litre to 10 litres are 300 K. Calculated the change in free energy of the gas `(R 8.314 JK^(-1)mol^(-1))`.

Explanation

For isothermal reversible process `Delta H = 0` and `Delta S = 2.303"nRT log"(V_(2))/(V_(1))`
`rArr Delta G=Delta H-T Delta S=-2.303 "nRT log"(V_(2))/(V_(1))=-2.303xx4xx8.314xx300"log"(10)/(1)=-22976.5 J`