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200 cm^(3) of 0.1 M H(2)SO(4) is mixed w...

`200 cm^(3)` of `0.1 M H_(2)SO_(4)` is mixed with `150 cm^(3)` of 0.2M KOH. Find the value of evolved heat.

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To find the value of evolved heat when `200 cm³` of `0.1 M H₂SO₄` is mixed with `150 cm³` of `0.2 M KOH`, we will follow these steps: ### Step 1: Calculate the number of moles of H₂SO₄ Using the formula for moles: \[ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} \] Convert the volume from cm³ to L: ...
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Calculate amount of heat evolved when (a) 500 cm^(3) of 0.5 hydrocloric acid is mixed with 200 cm^(3) of 0.8 M NaOH solution. (b) 250 cm^(3) of 0.4 M H_(2)SO_(4) is mixed with 500 cm^(3) of 0.2 M NaOH solution.

Whenever an acid is neutralised by a base, the net reaction is : H^(+)(aq) + OH^(-)(aq) to H_(2)O(l) + 57.1 kJ Calculate the heat evolved for the following experiments : (i) 0.25 mol of HCI solution is neutralised by 0.25 mol of NaOH solution. (ii) 0.60 mol of HNO_(3) solution is mixed with 0.30 mol of KOH solution. (iii) 100 cm^(3) of 0.2 M HCl is mixed with 200 cm^(3) of 0.3M NaOH. 400 cm^(3) of 0.2 M H_(2)SO_(4) is mixed with 600 cm^(3) of 0.1 M NaOH solution.

Knowledge Check

  • 200cm^(3) of 0.1MH_(2)SO_(4) is mixed with 150cm^(3) of 0.2 M KOH. Find the value of evolved heat.

    A
    1.7kJ
    B
    2.7kJ
    C
    9.2kJ
    D
    3.2kJ

  • When 50cm^(3) of 0.2N H_(2)SO_(4) is mixed with 50cm^(3) of 1 N KOH , the heat liberated is

    A
    11.46 kJ
    B
    57.3 kJ
    C
    573 kJ
    D
    573 J

  • When 50 cm^(3) of 0.2 N H_(2)SO_(4) is mixed with 50 cm^(3) of 1 N KOH , the heat liberated is

    A
    `11.46 kJ`
    B
    `57.3 kJ`
    C
    `573 kJ`
    D
    `573J`

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