Given that for a reaction of nth order, the integrated rate equation is:
`K=1/(t(n-1))[1/C^(n-1)-1/C_(0)^(n-1)]`, where `C` and `C_(0)` are the concentration of reactant at time `t` and initially respectively. The `t_(3//4)` and `t_(1//2)` are related as `t_(3//4)` is time required for C to become `C_(1//4`) :

Options

A. `t_(3//4)=t_(1//2) [2^((n-1))-1]`
B. `t_(3//4)=t_(1//2) [2^((n-1))+1]`
C. `t_(3//4)=t_(1//2) [2^((n+1))+1]`
D. `t_(3//4)=t_(1//2) [2^((n-1))+1]`

Answer

D