A flask contains 4.4g of `CO_(2)` gas. Calculate
(b) How many moles of `CO_(2)` gas does it contain?
(b)How many molecules of `CO_(2)` gas are present in the sample.
(c )How many atoms of oxygen are present in the given sample.( Atomic mass of C=12u, O=16)

Explanation

`"No. of moles"=("Given mass (m)")/("Gram molar mas (M)")=((4.4g))/(44"gmol"^(-1))=0.1"mol"`
(b) `"1 mole of "CO_(2)"has moleuces"=6.605xx10^(23)`
`"0.1 mole of "CO_(2)"has moleuces"=6.605xx10^(23)xx(0.1)=6.602xx10^(22)`
(c ) `CO_(2)=2O`
`"1 mole of "CO_(2)"has oxygen atoms"=2xxN_(A)`
`"0.11 mole of "CO_(2)"has oxygen atoms"=2xxN_(A)xx0.1`
`=2xx6.022x10^(23)xx0.1=1.204xx10^(24)"atoms"`