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The acceleration due to gravity at a hei...

The acceleration due to gravity at a height h is given by `g_(h)=g((R )/(R+h))^(2)`, where g is the accleeration due to gravity on the surface of earth. For `h lt lt R`, find the value of g using the Binomial theorem.

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To find the value of \( g_h \) at a height \( h \) using the Binomial theorem, we start with the formula given: \[ g_h = g \left( \frac{R}{R+h} \right)^2 \] where \( g \) is the acceleration due to gravity at the surface of the Earth, \( R \) is the radius of the Earth, and \( h \) is the height above the Earth's surface. We are given that \( h \) is much smaller than \( R \) (i.e., \( h \ll R \)). ...
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Let g be the acceleration due to gravity on the earth's surface.

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Knowledge Check

  • What will be the acceleration due to gravity at height h if h gt gt R . Where R is radius of earth and g is acceleration due to gravity on the surface of earth

    A
    `(g)/((1+h/R)^(2))`
    B
    `g(1-(2h)/R)`
    C
    `(g)/((1-h/R)^(2))`
    D
    `g(1-h/R)`
  • The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

    A
    `1//9`
    B
    `1//16`
    C
    `1//4`
    D
    `1//3`
  • What will be the acceleration due to gravity at height h lt lt R . Where R is radius of earth and g is acceleration to gravity on the surface earth

    A
    `(g)/((1 + (h)/(R))^(2))`
    B
    `g (1 - (2h)/(R))`
    C
    `(g)/((1 - (h)/(R))^(2))`
    D
    ` g (1 - (h)/(R))`
  • Similar Questions

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