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Let I1 and I2 be intensities of two sour...

Let `I_1 and I_2` be intensities of two sources such that `(I_1)/(I_2) = k`. Find value of `(I_("max") - I_("min"))/(I_("max") + I_("min"))`.

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To solve the problem, we need to find the value of \((I_{\text{max}} - I_{\text{min}})/(I_{\text{max}} + I_{\text{min}})\) given the relationship between the intensities of two sources \(I_1\) and \(I_2\) such that \(\frac{I_1}{I_2} = k\). ### Step-by-Step Solution: 1. **Understanding Maximum and Minimum Intensities**: - The maximum intensity \(I_{\text{max}}\) for two coherent sources is given by: \[ I_{\text{max}} = (\sqrt{I_1} + \sqrt{I_2})^2 ...
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Knowledge Check

  • Two coherent sources of intensity ratio alpha interfere. The value of (I_("max") - I_("min"))/(I_("max") + I_("min")) is ,

    A
    `2sqrt((alpha)/(1+alpha))`
    B
    `(2sqrt(alpha))/(1+alpha)`
    C
    `(1+alpha)/(2sqrt(alpha))`
    D
    `(1-alpha)/(1+alpha)`

  • The intensity ratio of the two interfering beams of light is m. What is the value of I_("max")-I_("min") // I_("max")+I_("min") ?

    A
    `2sqrt(m)`
    B
    `(2sqrt(m))/(1+m)`
    C
    `(2)/(1+m)`
    D
    `(1+m)/(2sqrt(m))`

  • Two coherent sources of intensity ratio alpha interface . In interference pattern (I_("max") - I_("min"))/(I_("max") + I_("min")) =

    A
    `(2 alpha )/(1 + alpha )`
    B
    `(2 sqrt alpha)/(1 + alpha)`
    C
    `(2alpha )/(1 + sqrtalpha)`
    D
    `(1 + alpha )/(2 alpha )`

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    Two coherent sources of intensity ratio beta interfere, then (I_(max)-I_(min))/(I_(max)+I_(min)) is

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