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Maximum kinetic energy of the photoelect...

Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation .
Give reason.

Text Solution

Verified by Experts

By Einstein.s photoelectric equation
`eV_1=hv_1-hv_0" "....(i)`
and
`eV_2=(hv_1)/2-hv_0`
`2eV_1=hv_1-2hv_0" "...(ii)`
Solving (i) and (ii) we have
`e(V_1-2V_2)=hv_0`
`v_0=(e(V_1-2V_2))/h`
the frequency is doubled , maximum kinetic energy will not doubled.
`K_(max)=hv-hv_0`
`K_("new")=2hv-hv_0=hv+K_(max)`
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Explain giving reasons for the following: (a) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation. (b) The stopping potential (V_(0)) varies linearly with the frequency (v) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces. (c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.

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Knowledge Check

  • The maximum kinetic energy of the photoelectrons veries

    A
    Inversely with the intensity and is independent of the frequency of the incident radiation
    B
    Inversely with the frequency and is independent of the intensity of the incident radiation
    C
    Linearly with the frequency and is independent of the intensity of the incident radiation
    D
    Linearly with the frequency and is independent of the intensity of the incident radiation

  • The maximum kinetic energy of the photoelectrons depends only on

    A
    Potential
    B
    frequency
    C
    incident angle
    D
    pressure

  • The maximum kinetic energy of emitted photoelectrons depends on

    A
    Intensity of incident radiation
    B
    Frequency of incident radiation
    C
    Speed of incident radiation
    D
    Number of photons in the accident radiation

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    Assertion: Kinetic energy of photoelectrons is directly proportinal of the intensity of the incident radiation. Reason: Each photo of light causes the emission of only one photoelectron.

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