Natural chlorine is composed of two isotopes `""_(17)Cl^(35)` and `""_(17)Cl^(37)` with masses 34.968 and 36.968, respectively. If their relative abundance are 75.18% and 24.22% respectively, calculate the composite atomic mass of the natural chlorine.

Explanation

To calculate the composite atomic mass of natural chlorine, we will use the formula for the weighted average of the isotopes based on their relative abundances.

### Step-by-Step Solution:

1. **Identify the isotopes and their masses:**
- Isotope 1: \( ^{35}\text{Cl} \) with mass \( m_1 = 34.968 \, \text{u} \)
- Isotope 2: \( ^{37}\text{Cl} \) with mass \( m_2 = 36.968 \, \text{u} \)

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