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In a nuclear explosion, 180 MeV energy w...

In a nuclear explosion, 180 MeV energy was released per fission and a total energy of `8 xx 10^(13)` joules was released. Calculate the mass of uranium used in the explosion.

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To solve the problem of calculating the mass of uranium used in a nuclear explosion, we will follow these steps: ### Step 1: Convert the energy released per fission from MeV to Joules The energy released per fission is given as 180 MeV. We need to convert this to Joules using the conversion factor \(1 \text{ MeV} = 1.6 \times 10^{-13} \text{ Joules}\). \[ \text{Energy per fission} = 180 \text{ MeV} \times 1.6 \times 10^{-13} \text{ Joules/MeV} = 2.88 \times 10^{-11} \text{ Joules} \] ### Step 2: Calculate the total number of fissions We know the total energy released in the explosion is \(8 \times 10^{13} \text{ Joules}\). To find the total number of fissions (or uranium atoms that underwent fission), we divide the total energy by the energy released per fission. \[ \text{Number of fissions} = \frac{\text{Total Energy}}{\text{Energy per fission}} = \frac{8 \times 10^{13} \text{ Joules}}{2.88 \times 10^{-11} \text{ Joules}} \approx 2.78 \times 10^{24} \text{ fissions} \] ### Step 3: Convert the number of fissions to moles To find the number of moles of uranium, we use Avogadro's number, which is approximately \(6.022 \times 10^{23} \text{ atoms/mole}\). \[ \text{Number of moles} = \frac{\text{Number of fissions}}{N_A} = \frac{2.78 \times 10^{24}}{6.022 \times 10^{23}} \approx 4.62 \text{ moles} \] ### Step 4: Calculate the mass of uranium The molar mass of uranium is approximately \(238 \text{ g/mol}\). To find the total mass of uranium used, we multiply the number of moles by the molar mass. \[ \text{Mass of uranium} = \text{Number of moles} \times \text{Molar mass} = 4.62 \text{ moles} \times 238 \text{ g/mol} \approx 1099.56 \text{ grams} \] ### Final Answer The mass of uranium used in the explosion is approximately **1099.56 grams**. ---
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It is estimated that the atomic bomb exploded at Hiroshima released a total energy of 7.6xx10^(13)J . If on the average, 200MeV energy was released per fission, calculate (i) the number of Uranium atoms fissioned, (ii) the mass of Uranium used in the bomb.

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Knowledge Check

  • In a nuclear explosion, the energy is released in the form of

    A
    Thermal energy
    B
    Kinetic energy
    C
    Potential energy
    D
    Electrical energy
  • In nuclear fission process , energy is released because

    A
    mass of products is more than mass of nucleus
    B
    total binding energy of products formed due to nuclear fission is more than the parent fissionable material
    C
    Total binding energy of products formed due to nuclear fission is less than parent fissionable material
    D
    mass of some particles is converted into energy
  • Per unit mass released energy is

    A
    same in nuclear fusion and fission
    B
    more in fusion as compare to fission
    C
    more in fission as compare to fusion
    D
    changed at different times
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    An explosion of atomic bomb releases an energy of 7.6xx10^(13)J . If 200 MeV energy is released on fission of one .^(235)U atom calculate (i) the number of uranium atoms undergoing fission. (ii) the mass of uranium used in the atom bomb

    Why a huge amount of energy is released in nuclear fission of nuclear fusion solution.

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