Home
Class 12
PHYSICS
A sample of an element is 10.38 g. If ha...

A sample of an element is 10.38 g. If half-life of element is 3.8 days, then after 19 days how much quantity of element remains?

A

0.151g

B

0.32 g

C

1.51 g

D

0.16 g

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much quantity of an element remains after a certain period given its half-life, we can follow these steps: ### Step 1: Identify the initial quantity and half-life - The initial quantity of the element is given as \( m_0 = 10.38 \, \text{g} \). - The half-life of the element is \( t_{1/2} = 3.8 \, \text{days} \). ### Step 2: Determine the total time elapsed - The total time elapsed is given as \( t = 19 \, \text{days} \). ### Step 3: Calculate the number of half-lives - To find the number of half-lives that have passed in 19 days, we use the formula: \[ n = \frac{t}{t_{1/2}} = \frac{19 \, \text{days}}{3.8 \, \text{days}} = 5 \] - This means that 5 half-lives have passed. ### Step 4: Apply the half-life formula - The remaining quantity of the element after \( n \) half-lives can be calculated using the formula: \[ m = m_0 \left(\frac{1}{2}\right)^n \] - Substituting the values we have: \[ m = 10.38 \, \text{g} \left(\frac{1}{2}\right)^5 \] ### Step 5: Calculate \( \left(\frac{1}{2}\right)^5 \) - Calculate \( \left(\frac{1}{2}\right)^5 \): \[ \left(\frac{1}{2}\right)^5 = \frac{1}{32} \] ### Step 6: Calculate the remaining quantity - Now substitute this back into the equation: \[ m = 10.38 \, \text{g} \times \frac{1}{32} = \frac{10.38}{32} \approx 0.324 \, \text{g} \] ### Step 7: Conclusion - After 19 days, approximately \( 0.324 \, \text{g} \) of the element remains. ### Final Answer - The remaining quantity of the element after 19 days is approximately \( 0.324 \, \text{g} \). ---

To solve the problem of how much quantity of an element remains after a certain period given its half-life, we can follow these steps: ### Step 1: Identify the initial quantity and half-life - The initial quantity of the element is given as \( m_0 = 10.38 \, \text{g} \). - The half-life of the element is \( t_{1/2} = 3.8 \, \text{days} \). ### Step 2: Determine the total time elapsed - The total time elapsed is given as \( t = 19 \, \text{days} \). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (JEE MAIN & OTHER STATE BOARDS FOR ENGINEERING ENTRANCES)|19 Videos
  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (JEE ADVANCED FOR IIT ENTRANCES)|3 Videos
  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) (MULTIPLE CHOICE QUESTIONS)|20 Videos
  • MOVING CHARGES AND MAGNETISM

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|13 Videos
  • RAY OPTICS AND OPTICAL INSTRUMENTS

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

Half life of a ratio-active element is 8 years, how much amount will be present after 32 years ?

The half-life of radon is 3.8 days. After how many days 19/20 of the sample will decay ?

Knowledge Check

  • Half life of a radioactive sample is 4 days. After 16 days how much quantity of matter remain undecayed :

    A
    `1/4`
    B
    `1/8`
    C
    `1/16`
    D
    `1/32`
  • Half-life of an element A is 25 days. After 25 days , three atoms of A become

    A
    1
    B
    2
    C
    3
    D
    all may be
  • A saample of radioactive elements contains 4xx10^(16) active nuclei. If half-life of element is 10 days, then the number of decayed nuclei after 30 days is

    A
    `0.5xx10^(10)`
    B
    `2xx10^(10)`
    C
    `3.5xx10^(10)`
    D
    `1xx10^(10)`
  • Similar Questions

    Explore conceptually related problems

    The half-life periof of a radioactive element is 40 days. If 32 g of this element is stored for 160 days , calculate the weight of the element that would remain in gram.

    The half-life of radon is 3.8 days. Calculate how much radon will be left out of 25 mg after 19 days.

    The half-life of radon is 3.8 days. Three forth of a radon sample decay in.

    The half-life period of radioactive element is 140 days. After 560 days, 1 g of element will reduce to

    The half life period of radio active element is 140 days. After 560 days 1gm of element will reduce to