A block of mass 2 kg is dropped from a height of 0-4 mon a spring whose force constant is 1960 N/m. What will be the maximum distance x of the compression of the spring ?

Options

A. 0.5 m
B. 0.1 m
C. 0.01 m
D. 1 m

Answer

b

Explanation

P.E. of spring = loss in P.E. of body
`1/2 kx^(2)=mg(h+x)`
`2(0.4+x)9.8=(1)/(2)1960xxx^(2)`
`19.6(0.4+x)=980 x^(2)`
Which gives on solving, the quadratic `x=(1)/(10)=0.1 m`