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A block of mass 0.50 kg is moving with s...

A block of mass 0.50 kg is moving with speed of `2.00 ms^(-1)` on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collisions is

A

0.16 J

B

1.00 J

C

0.67 J

D

0.34 J

Text Solution

Verified by Experts

The correct Answer is:
c
Initial kinetic energy of the system
`KE_i=1/2"mu"^2+1/2M(0)^2=1/2xx0.5xx2xx2+0=1J`
For collision applying conservation of linear momentum `mxxu=(m+M)xxv`
`:. 0.5xx2=(0.5+1)xxvimplies v=2/3 m//s`
Final kinetic energy of the system is
`KE_f=1/2(m+M)v^2=1/2(0.5+1)xx2/3xx2/3=1/3J`
`:.` Energy loss during collision=`(1-1/3)J=0.67J`
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Knowledge Check

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