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The moment of inertia of a circular disc...

The moment of inertia of a circular disc of radius 2 m and mass 1 kg about an axis passing through the centre of mass but perpendicular to the plane of the disc is 2 kg `m^(2)`. Its moment of inertia about an axis parallel to this axis but passing through the edge of the disc is :

A

`10kgm^(2)`

B

`6kgm^(2)`

C

`8kgm^(2)`

D

`1kgm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
By theorem of parallel axis
`I_(x,y)=I_(x,y)+Ml^(2)=2+1xx(2)^(2)`
`=6kgm^(2)`
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Knowledge Check

  • The moment of inertia of a circular ring of radius r and mass M about diameter is

    A
    `2/5 Mr^(2)`
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    A
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