The moment of inertia of a circular disc of radius 2 m and mass 1 kg about an axis passing through the centre of mass but perpendicular to the plane of the disc is 2 kg `m^(2)`. Its moment of inertia about an axis parallel to this axis but passing through the edge of the disc is :

Options

A. `10kgm^(2)`
B. `6kgm^(2)`
C. `8kgm^(2)`
D. `1kgm^(2)`

Answer

B

Explanation

By theorem of parallel axis
`I_(x,y)=I_(x,y)+Ml^(2)=2+1xx(2)^(2)`
`=6kgm^(2)`