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A short bar magnet of amgnetic moment 25...

A short bar magnet of amgnetic moment 25 `JT^(-1)` is placed with its axis perpendicular to earth the resultant field is inclined at `45^(@)` with earth field if `H=0.4xx10^(-4)`T

A

5m

B

0.5 m

C

2.5 m

D

0.25 m

Text Solution

Verified by Experts

The correct Answer is:
B

Since B and H are to each other and resultant field is inclined at an angle `45^(@)` with
so B=H
`therefore (mu_(0))/(4pi)(2M)/(r^(3))=H`
`therefore r^(3)=(mu_(0))/(4pi)(2M)/(H)=0.5 m`
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Knowledge Check

  • A short bar magnet of magnetic moment 25JT^(-1) is placed with its axis perpendicular to earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45^(@) with earth's field, if H=0.4xx10^(-4)T .

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    B
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    D
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