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Consider the isoelectronic species, Na^(...

Consider the isoelectronic species, `Na^(+),Mg^(2+),F^(-)` and `O^(2-)`. The correct order of increasing length of their radii is:

A

`F ^(-) lt O ^(2-) lt Mg ^(2+) lt Na ^(+)`

B

`Mg ^(2+) lt Na ^(+) lt F ^(-) lt O ^(2-)`

C

`O ^(2-) lt F ^(-) lt Na ^(+) lt Mg ^(2+)`

D

`O ^(2-) lt F ^(-) lt Mg ^(2+) lt Na ^(+)`

Text Solution

Verified by Experts

The correct Answer is:
B
Amongst isoelectronic ions, ionic radii decrease with increase in nuclear charge :
`Mg ^(2+) (12) lt Na ^(+) (11) lt F ^(-) (10) lt O^(2-) (8)`
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Knowledge Check

  • The correct order of increasing radii are

    A
    `Be^(2+), Mg^(2+), Na^(o+)`
    B
    `K^(o+), Ca^(2+), S^(2-)`
    C
    `O^(2-), F^(ɵ), N^(3-)`
    D
    `S^(2-), O^(2-), As^(3-)`

  • Consider the isoelectronic species Na^+,Mg^+2,F^-and O^-2 the correct order of their increasing ionic radii is….

    A
    `F^-ltO^-2ltMg^+2ltNa^+`
    B
    `Mg^+2ltNa^+ltF^-ltO^-2`
    C
    `O^-2ltF^-ltNa^+ltMg^+2`
    D
    `O^-2ltF^-ltMg^+2ltNa^+`

  • For Na^(+), Mg^(2+),F^(-) and O^(2-) , the correct order of increasing ionic radii is

    A
    `Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-)`
    B
    `O^(2-) lt F^(-) lt Na^(+) lg Mg^(2+)`
    C
    `Na^(+) lt Mg^(2+) lt F^(-) lt O^(2-)`
    D
    `Mg^(2+) lt O^(2-) lt Na^(+) lt F^(-)`

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