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The energy of a photon is given as: Delt...

The energy of a photon is given as: `DeltaE//"atom"=3.03xx10^(-19)J"atom"^(-1)`. The wavelength `(lamda)` of its photon is

A

65.6 nm

B

656nm

C

0.565nm

D

6.56nm

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaE=hv=(hc)/(lamda)`
or `lamda=(hc)/(DeltaE)=((6.636xx10^(-34)Js)xx(3.0xx10^(8)))/(3.03xx10^(-10))`
`=6.65xx10^(-7)m=656m`
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Knowledge Check

  • The energy of a photon is 3.03 xx 10^-19 J atom^-1 Wavelength of photon is

    A
    65.6 nm
    B
    656 nm
    C
    0.656 nm
    D
    6.56 nm.

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    `3xx10^(3)Hz`
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    `7.5xx10^(12)Hz`
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